Optimal. Leaf size=80 \[ \frac{x^{22}}{22}+\frac{11 x^{20}}{20}+\frac{55 x^{18}}{18}+\frac{165 x^{16}}{16}+\frac{165 x^{14}}{7}+\frac{77 x^{12}}{2}+\frac{231 x^{10}}{5}+\frac{165 x^8}{4}+\frac{55 x^6}{2}+\frac{55 x^4}{4}+\frac{11 x^2}{2}+\log (x) \]
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Rubi [A] time = 0.0332073, antiderivative size = 80, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {28, 266, 43} \[ \frac{x^{22}}{22}+\frac{11 x^{20}}{20}+\frac{55 x^{18}}{18}+\frac{165 x^{16}}{16}+\frac{165 x^{14}}{7}+\frac{77 x^{12}}{2}+\frac{231 x^{10}}{5}+\frac{165 x^8}{4}+\frac{55 x^6}{2}+\frac{55 x^4}{4}+\frac{11 x^2}{2}+\log (x) \]
Antiderivative was successfully verified.
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Rule 28
Rule 266
Rule 43
Rubi steps
\begin{align*} \int \frac{\left (1+x^2\right ) \left (1+2 x^2+x^4\right )^5}{x} \, dx &=\int \frac{\left (1+x^2\right )^{11}}{x} \, dx\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{(1+x)^{11}}{x} \, dx,x,x^2\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \left (11+\frac{1}{x}+55 x+165 x^2+330 x^3+462 x^4+462 x^5+330 x^6+165 x^7+55 x^8+11 x^9+x^{10}\right ) \, dx,x,x^2\right )\\ &=\frac{11 x^2}{2}+\frac{55 x^4}{4}+\frac{55 x^6}{2}+\frac{165 x^8}{4}+\frac{231 x^{10}}{5}+\frac{77 x^{12}}{2}+\frac{165 x^{14}}{7}+\frac{165 x^{16}}{16}+\frac{55 x^{18}}{18}+\frac{11 x^{20}}{20}+\frac{x^{22}}{22}+\log (x)\\ \end{align*}
Mathematica [A] time = 0.0032637, size = 80, normalized size = 1. \[ \frac{x^{22}}{22}+\frac{11 x^{20}}{20}+\frac{55 x^{18}}{18}+\frac{165 x^{16}}{16}+\frac{165 x^{14}}{7}+\frac{77 x^{12}}{2}+\frac{231 x^{10}}{5}+\frac{165 x^8}{4}+\frac{55 x^6}{2}+\frac{55 x^4}{4}+\frac{11 x^2}{2}+\log (x) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.001, size = 59, normalized size = 0.7 \begin{align*}{\frac{11\,{x}^{2}}{2}}+{\frac{55\,{x}^{4}}{4}}+{\frac{55\,{x}^{6}}{2}}+{\frac{165\,{x}^{8}}{4}}+{\frac{231\,{x}^{10}}{5}}+{\frac{77\,{x}^{12}}{2}}+{\frac{165\,{x}^{14}}{7}}+{\frac{165\,{x}^{16}}{16}}+{\frac{55\,{x}^{18}}{18}}+{\frac{11\,{x}^{20}}{20}}+{\frac{{x}^{22}}{22}}+\ln \left ( x \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.973522, size = 84, normalized size = 1.05 \begin{align*} \frac{1}{22} \, x^{22} + \frac{11}{20} \, x^{20} + \frac{55}{18} \, x^{18} + \frac{165}{16} \, x^{16} + \frac{165}{7} \, x^{14} + \frac{77}{2} \, x^{12} + \frac{231}{5} \, x^{10} + \frac{165}{4} \, x^{8} + \frac{55}{2} \, x^{6} + \frac{55}{4} \, x^{4} + \frac{11}{2} \, x^{2} + \frac{1}{2} \, \log \left (x^{2}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.66668, size = 193, normalized size = 2.41 \begin{align*} \frac{1}{22} \, x^{22} + \frac{11}{20} \, x^{20} + \frac{55}{18} \, x^{18} + \frac{165}{16} \, x^{16} + \frac{165}{7} \, x^{14} + \frac{77}{2} \, x^{12} + \frac{231}{5} \, x^{10} + \frac{165}{4} \, x^{8} + \frac{55}{2} \, x^{6} + \frac{55}{4} \, x^{4} + \frac{11}{2} \, x^{2} + \log \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.10352, size = 75, normalized size = 0.94 \begin{align*} \frac{x^{22}}{22} + \frac{11 x^{20}}{20} + \frac{55 x^{18}}{18} + \frac{165 x^{16}}{16} + \frac{165 x^{14}}{7} + \frac{77 x^{12}}{2} + \frac{231 x^{10}}{5} + \frac{165 x^{8}}{4} + \frac{55 x^{6}}{2} + \frac{55 x^{4}}{4} + \frac{11 x^{2}}{2} + \log{\left (x \right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.10755, size = 84, normalized size = 1.05 \begin{align*} \frac{1}{22} \, x^{22} + \frac{11}{20} \, x^{20} + \frac{55}{18} \, x^{18} + \frac{165}{16} \, x^{16} + \frac{165}{7} \, x^{14} + \frac{77}{2} \, x^{12} + \frac{231}{5} \, x^{10} + \frac{165}{4} \, x^{8} + \frac{55}{2} \, x^{6} + \frac{55}{4} \, x^{4} + \frac{11}{2} \, x^{2} + \frac{1}{2} \, \log \left (x^{2}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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